.hello : an equation of the circle Center at the w(a,b) and ridus : r is : (x-a)² +(y-b)² = r² in this exercice : r = 1 The points (-18,15) and (-20,15) lie on a circle with a radius of 1: (-18-a)²+(15-b)² = 1 ....(1) (-20-a)² +(15-b)² = 1 ....(2) solve this system : (1) -(2) : (-18-a)² - (-20-a)² =0 (-18-a)² =(-20-a)² =0 ( -18-a = -20-a) or (-18-a = - (-20-a)) 1 ) ( -18-a = -20-a) no solution confused : -18=-20 2 ) -18-a =20+a -2a =38 a = -19 subst in (1) :(-18+19)²+(15-b)² =1 (15-b)² = 0.... 15-b = 0 .... b = 15 the center is :w(-19,15)