Question

What is the standard form of equation of a circle with center at (-2, -3) and passing through the point (-2, 0)?

Answer 1

hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2  and b =-3  (Center A(-2,-3))
r = AP......(P(-2,0))
r² = (AP)²
r² = (-2+2)² +(-3-0)² = 9
an equation of the circle that satisfies the stated conditions.
Center  A(-2,-3) , passing through P(-2, 0) is : (x+2)² +(y+3)² = 9