Respuesta :
Answer:
The given statement is:
TRUE.
( i.e. [tex]h=\dfrac{v_0^2}{32}\times \sin 2\theta[/tex] )
Step-by-step explanation:
We are given the horizontal distance, in feet, traveled by a projectile can be modeled by the equation.
[tex]h=\dfrac{v_0^2}{16}\times \sin\theta \cos\theta[/tex]
now we multiply and divide by 2 (i.e. the same quantity is multiplied in the numerator and the denominator) to get:
[tex]h=\dfrac{v_0^2}{16\times 2}\times 2\times \sin\theta \cos\theta[/tex]
We know that:
[tex]2\sin\theta \cos\theta=\sin 2\theta[/tex]
Hence, we get:
[tex]h=\dfrac{v_0^2}{32}\times \sin 2\theta[/tex]
Hence, the given statement is TRUE statement.