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TRUE or FALSE The horizontal distance, in feet, traveled by a projectile can be modeled by the equation.. h = ((v0^2)/16) sinθcosθ ..where θ is the initial angle and v0 is the initial velocity. This simplifies to h = ((v0^2)/32) sin(2θ) .

Respuesta :

the answer is TRUE hope this helped

Answer:

The given statement is:

TRUE.

( i.e. [tex]h=\dfrac{v_0^2}{32}\times \sin 2\theta[/tex] )

Step-by-step explanation:

We are given the horizontal distance, in feet, traveled by a projectile can be modeled by the equation.

[tex]h=\dfrac{v_0^2}{16}\times \sin\theta \cos\theta[/tex]

now we multiply and divide by 2 (i.e. the same quantity is multiplied in the numerator and the denominator) to get:

[tex]h=\dfrac{v_0^2}{16\times 2}\times 2\times \sin\theta \cos\theta[/tex]

We know that:

[tex]2\sin\theta \cos\theta=\sin 2\theta[/tex]

Hence, we get:

[tex]h=\dfrac{v_0^2}{32}\times \sin 2\theta[/tex]

Hence, the given statement is  TRUE statement.

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