I need help with 9-81 ASAP PLS THIS IS MY HW

*Plus I will give you 5 stars and if the answer is specific and clear, I will also mark you as the brainiest answer. *

I need help with 981 ASAP PLS THIS IS MY HWPlus I will give you 5 stars and if the answer is specific and clear I will also mark you as the brainiest answer class=

Respuesta :

it is -72 lol. that's pretty basic you know
To start, we know that the equation we are trying to find is a straight line. It hits the x-axis at -3 and the y-axis at -1.
Thus, we know that the line passes through (0, -1) and (-3, 0).

We can now find the gradient using the gradient form: [tex]\frac{y_1 - y_2}{x_1 - x_2}[/tex]

Thus, the gradient becomes: [tex]m = \frac{0 - (-1)}{-3 - 0}[/tex]
[tex]m = -\frac{1}{3}[/tex]

Since we have a point of interest and a gradient, we can use the point-gradient form of a straight line to find the equation of the straight line.
[tex]y - y_1 = m(x - x_1)[/tex]

Use either the y-intercept or the x-intercept as your point.
[tex]y + 1 = -\frac{1}{3}(x - 0)[/tex]
[tex]y + 1 = -\frac{1}{3}x[/tex]

Thus, the equation becomes:
[tex]y = -\frac{1}{3}x - 1[/tex]

Now, since the shaded region is below the line, we know that the inequality becomes:

[tex]y \leq -\frac{1}{3}x - 1[/tex]

But, since it's dotted, we need to exclude the line itself.
Thus, the inequality becomes:
[tex]y < -\frac{1}{3}x - 1[/tex]
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