Since it's a linear graph, the graph will cut the x and y-axis once and once only.
Now, we can find where the x and y-intercepts are located.
x-intercept is found when we substitute y as 0.
[tex]0 = \frac{1}{2}x + 2[/tex]
[tex]-2 = \frac{1}{2}x[/tex]
[tex]-4 = x[/tex]
Thus, we know that the point (-4, 0) will pass through the graph.
Now, similarly, to find the y-intercept, we let x = 0.
[tex]f(0) = \frac{1}{2}(0) + 2[/tex]
[tex]y = 2[/tex]
Thus, we know that the point (0, 2) will pass through the graph.
We also know it has a positive gradient, so just join the dots to find the graph's shape.
Refer to Herontewodros for the correct graph.
