Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and they are both dimes. He says the probability of that occurring is 1 4 because 2 of the 8 coins are dimes. Is he correct? Explain.

He is incorrect because the probability of pulling a dime out of his pocket is 2/8 but if he wishes to pull a dime again his probability would be 1/7. To find the total probability you would need to times the numbers which then gives you 2/56 but if you simplify you get 1/28 meaning you have a 1 in 28 chance of pulling two dimes in a row.

fichoh fichoh · Answer 2 · 2021-10-15T12:32:03+02:00

The probability of randomly pulling out 2 dimes from his pocket is 1/28. Hence, Michael is wrong

Given the Parameters :

Dimes = 2
Quarters = 3
Nickels = 3
Total coins = (2 + 3 + 3) = 8

Recall :

Probability = required / total possible outcomes

First pick :

P(dime) = 1/8

Second pick :

Dimes left = 2 - 1 = 1

Total coins left = 8 - 1 = 7

P(dime) = 1/7

Therefore, P(2 dimes) = (2/8 × 1/7) = 2/56 = 1/28

Hence, Michael is incorrect.

Learn more :https://brainly.com/question/18153040