Respuesta :
Three hydrogen will provide three valence electrons and nitrogen has five valence electrons all in all they 8 valence electron
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H*«N«*H=NH3
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H
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H*«N«*H=NH3
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H
Answer : Ammonia has molecular formula as [tex] NH_{3} [/tex]
It has a central atom as Nitrogen bonded with 3 molecules of hydrogen around it, Nitrogen has atomic number 7
The electronic configuration of N is [tex] 1s^{2} 2s^{2} 2p^{3} [/tex]
The number of valence electrons are 5 in the outermost shell of nitrogen.
According to the octet rule, it needs 3 electrons to be an octet.
So, the valency of N is 3. And, Hydrogen has the valency as 1.
Therefore, three hydrogen are needed to be a stable compound of [tex] NH_{3} [/tex].
The lewis structure of [tex] NH_{3} [/tex] is attached in the answer.
In the attached figure, the electrons of N are shown in dot and the electrons of H are shown in x.
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