Respuesta :
if we take 8200 as the 100%, then [tex]\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
8200&100\\
x&80
\end{array}\implies \cfrac{8200}{x}=\cfrac{100}{80}\implies \boxed{?}
\\\\\\
\textit{so, the man lost }8200-\boxed{?}[/tex]
solve for "x"
well, the opposite of 20, will then be -20, their difference is then (20) - (-20)
how much is that amount of 200 in percentage? well, if we take 200 as the 100%
then [tex]\bf \begin{array}{ccllll} amount&\%\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ 200&100\\ (20)-(-20)&x \end{array}\implies \cfrac{200}{(20)-(-20)}=\cfrac{100}{x}[/tex]
solve for "x"
solve for "x"
well, the opposite of 20, will then be -20, their difference is then (20) - (-20)
how much is that amount of 200 in percentage? well, if we take 200 as the 100%
then [tex]\bf \begin{array}{ccllll} amount&\%\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ 200&100\\ (20)-(-20)&x \end{array}\implies \cfrac{200}{(20)-(-20)}=\cfrac{100}{x}[/tex]
solve for "x"