Question

∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 72° and minor arc CD = 132°, what is the measure of ∠ABD?

Answer 1

check the picture below

Answer 2

Answer: 42°

Step-by-step explanation:

First, find the minor arc AD.

arc AD=360-72-123=156

Then, ∆ABD=1/2(minor arc AD- minor arc AC)

∆ABD=1/2 (156-72)

∆ABC=1/2 84

∆ABC=42°