A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track. If the car started from rest at the top of a hill, how much higher was that point on the track than the lowest point?
The only thing acting as the roller coaster gets to the bottom is gravity thus acceleration is 9.81
so u use the formula vf^2 = vi^2 + 2abetaD thus distance = vf^2 - vi^2 divided by 2a so 26^2 - 0^2 divided by 2(9.81m/s) equals 676 divided by 2(9.81m/s) = 34.45463812m then use the appropriate 3 sig digs so 34.5m hopes this helps
