Mr. Walker gave his class the function f(x) = (x + 3)(x + 5). Four students made a claim about the function. Each student’s claim is below.
Jeremiah: The y-intercept is at (15, 0).
Lindsay: The x-intercepts are at (–3, 0) and (5, 0).
Stephen: The vertex is at (–4, –1).
Alexis: The midpoint between the x-intercepts is at (4, 0).
Which student’s claim about the function is correct?

Respuesta :

Answer:

Stephen's claim is correct.

Step-by-step explanation:

The given function is

[tex]f(x)=(x+3)(x+5)[/tex]

Put x=0 to find the y-intercepts.

[tex]f(0)=(0+3)(0+5)=3\times 5=15[/tex]

The y-intercept of the function is at (0,15). It means jeremiah's statement is incorrect.

Put f(x)=0, to find the x-intercept.

[tex]0=(x+3)(x+5)[/tex]

[tex]x+3=0\Rightarrow x=-3[/tex]

[tex]x+5=0\Rightarrow x=-5[/tex]

The x-intercepts are at (-3,0) and (-5,0). It means Lindsay's statement is incorrect.

[tex]f(x)=(x+3)(x+5)[/tex]

[tex]f(x)=x^2+8x+15[/tex]

[tex]f(x)=x^2+8x+15+16-16[/tex]

[tex]f(x)=(x^2+8x+16)-1[/tex]

[tex]f(x)=(x+4)^2-1[/tex]                 .... (1)

The vertex form of a parabola is

[tex]f(x)=(x-h)^2+k[/tex]                .... (2)

Where, (h,k) is vertex.

From (1) and (2) it is clear that the vertex of the parabola is (-4,-1), Stephen's claim is correct.

The midpoint between the x-intercepts is

[tex](\frac{-3-5}{2},\frac{0+0}{2})=(-4,0)[/tex]

The midpoint between the x-intercepts is at (-4, 0). It means Alexis's statement is incorrect.

Answer:

On E2020 its Stephen is correct

Step-by-step explanation:

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