Question

What equation can be solved to find the time when the pumpkin is 10 feet from the ground

Answer 1

h(t)=h0+vt-(at^2)/2  we can assume that this problem is near to the earth's surface so a≈32ft/s^2

h(t)=h0+vt-16t^2  now you need to plug in the initial velocity where v is and the initial height where h0 is...