Question

Factor completely 56a2b3 − 35ab


most helpful answer gets brainliest (that means shows how you got the answer)

Answer 1

The greatest common factor is 7ab so:

7ab(8ab^2-5)

....  just in case you are unsure...

The greatest common factor of any two numbers is the product of shared primes from their prime factorization, in this case:

56=2*2*2*7 and 35=5*7, so the only shared prime(s) are 7 so that is the greatest common factor....

The greatest common factor of similar based exponential terms is the base raised to the power of the least power.  And upon division, the rule is:

(a^c)/(a^b)=a^(c-b)

Answer 2

$56a^{2}b^{3}-35ab$
First, factor out the greatest common factor(GCF) of the two terms:
$56a^{2}b^{3}-35ab\\ 2(2)(2)(7)(a)(a)(b)(b)(b)(b)-5(7)(a)(b)\\(7*a*b)(8ab^{2}-5)\\7ab(8ab^{2}-5)$
The expression doesn't factor any farther, so your answer is 7ab(8ab^2 - 5).