Question

The coordinates of the vertices of triangle XYZ are given in the table.

X Y Z
(0,−6) (−10,4) (3,−1)


Triangle XYZ is reflected across the y-axis.

What are the vertices of triangle X'Y'Z'?



Enter your answers in the boxes.

X': (
, ​
​)

Y': (
, ​
​)

Z': (
, ​
​)

Answer 1

X': (0,-6)
Y':(10,4)
Z':(-3,-1)

Answer 2

Answer: X'(0,6)   Y'(10,4)   Z'(-3,-1)

Step-by-step explanation:

Given: Triangle XYZ is reflected across the y-axis.

The coordinates of the vertices of triangle XYZ are

X(0,−6) Y(−10,4) Z(3,−1)

 

We know that the rule for a reflection over the y -axis is

$(x,y)\rightarrow(-x,y)$ .

Then, the coordinates of X'Y'Z' will be

$X(0,6)\rightarrow X'(0,6)$

$Y(-10,4)\rightarrow Y'(10,4)$

$Z(3,-1)\rightarrow Z'(-3,-1)$