Question

YZ has endpoint Y(-1,-11) and Z(-1-3) Find the length of YZ to the nearest tenth

Answer 1

Answer 8

Distance formula sq rt of. (-3--11)^2+(-1--1)^2.( -3+11) = (8)^2 +0
Sq rt of 64 is 8

Answer 2

≡ We know that:
⇔ $Y(-1,-11)$
⇔ $Z(-1,-3)$

≡ Solution:
⇒ $YZ= \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}$
⇒ $YZ=\sqrt{(-1-(-1))^{2}+(-3-(-11))^{2}}}$
⇒ $YZ=\sqrt{(0)^{2}+(8)^{2}}}$
⇒ $YZ=\sqrt{64}=\boxed{8}$