Question

Find the escape velocity ve for an object of mass m that is initially at a distance r from the center of a planet of mass m. assume that r≥rplanet, the radius of the planet, and ignore air resistance.

Answer 1

We are given
m = mass of the object
r = distance from the center of the planet
r ≥ rplanet

We are asked for the
ve = escape velocity

The escape velocity
ve = √ (2Gm/r)

Answer 2

The escape velocity for an object of mass m that is initially at a distance r will be $\rm v = \sqrt{\frac{2Gm}{r} }$.

What is escape velocity?

Escape velocity or escape speed is the minimum speed required for a free, non-propelled object to escape from the gravitational pull of the main body and reach an infinite distance from it in celestial physics.

It is commonly expressed as an ideal speed, neglecting atmospheric friction.

The formula for the escape velocity is;

$\rm v = \sqrt{\frac{2Gm}{r} }$

Hence the escape velocity for an object of mass m that is initially at a distance r will be $\rm v = \sqrt{\frac{2Gm}{r} }$.

To learn more about the escape velocity refer to the link;

https://brainly.com/question/14297933