By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.
Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:
[tex]y - y_1 = \frac{1}{2}(x - x_1)[/tex], where [tex](x_1, y_1)[/tex] represents the points being passed through.
[tex]y - 4 = \frac{1}{2}(x + 6)[/tex]
[tex]2y - 8 = x + 6[/tex]
[tex]2y = x + 14[/tex]
[tex]y = \frac{1}{2}x + 7[/tex]