We assume in this number that the fence is in a rectangular shape such that its perimeter is equal to,
P = 2x + 2y
From the equation of the area,
A = xy = 1000 ; x = 1000/y
Substituting this to the equation,
P = 2(1000/y) + 2
P = 2000/y + 2y
Getting the differential and equating it to zero.
dP = -2000/y²+ 2 = 0
The value of y from the equation is 31.62 yd
The value of x:
x = 1000/31.62 = 31.62 yd
Therefore, the dimension of the area to be fenced is 31.62 yd by 31.62 yd.