Question

multiply the following polynomial and write the resulting polynomial in descending order. (3x-8)(2x^2+4x-9)

Value of the coefficient of the x^3 term is

Value of the coefficient of the x^2 term is

Value of the coefficient of the x term is

The value of the constant is

Answer 1

$(3x-8)(2x^2+4x-9)=6x^3+12x^2-27x-16x^2-32x+72=6x^3-4x^2-59x+72$

Value of the coefficient of the $x^3$ term is $\boxed{6}$

Value of the coefficient of the $x^2$ term is $\boxed{-4}$

Value of the coefficient of the x term is $\boxed{-59}$

The value of the constant is $\boxed{72}$

:)