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Using (6C3 x 9C4)/ 15C7 to find probability of 3 out of 6 youtube and 4 out of 6 online divided by 7 out of 15 total
Using (6C3 x 9C4)/ 15C7 to find probability of 3 out of 6 youtube and 4 out of 6 online divided by 7 out of 15 total
Answer: [tex]\frac{7}{450450}[/tex]
Step-by-step explanation:
Here, the number of you tube videos = 6,
The number of online role-playing games = 9,
⇒ Total number of games = 6 + 9 = 15,
Hence, the probability of choosing three you tube video and 4 online role playing games out of 7 chosen games,
[tex]=\frac{^6C_{3}\times ^9C_{4}}{^15C_{7}}[/tex]
[tex]=\frac{4\times 126}{32432400}[/tex]
[tex]=\frac{504}{32432400}[/tex]
[tex]=\frac{7}{450450}[/tex]