Respuesta :
This is a simple fraction dividing problem.
you need to divide [tex] \frac{1}{9}[/tex] and [tex]5.[/tex]
Also known as [tex] \frac{1}{9} [/tex] ÷ the reciprocal of [tex] \frac{5}{1} [/tex]. So how do you do this? I know a strategy called "Keep Change Flip" meaning you keep the first number, in this case you keep [tex] \frac{1}{9}[/tex], you change the division sign into multiplication, and you flip [tex] \frac{5}{1} [/tex] into [tex] \frac{1}{5} [/tex]. Now you multiply.
[tex] \frac{1}{9} [/tex] × [tex] \frac{1}{5} [/tex]
1 × 1 = 1
9 × 5 = 45
You get [tex] \frac{1}{45} [/tex]. This is your answer.
you need to divide [tex] \frac{1}{9}[/tex] and [tex]5.[/tex]
Also known as [tex] \frac{1}{9} [/tex] ÷ the reciprocal of [tex] \frac{5}{1} [/tex]. So how do you do this? I know a strategy called "Keep Change Flip" meaning you keep the first number, in this case you keep [tex] \frac{1}{9}[/tex], you change the division sign into multiplication, and you flip [tex] \frac{5}{1} [/tex] into [tex] \frac{1}{5} [/tex]. Now you multiply.
[tex] \frac{1}{9} [/tex] × [tex] \frac{1}{5} [/tex]
1 × 1 = 1
9 × 5 = 45
You get [tex] \frac{1}{45} [/tex]. This is your answer.