Question

A particular Algebra text has a total of 1382 pages which is broken into two parts. The second part of the book has 64 more pages than the first part. how many pages are in each part of the book? please show work.

Answer 1

You can say that the first part of the book has (x) number of pages.  That would mean that the second part has (x+64) pages.  To find the actual number of pages, set up an equation and solve for (x).


Equation                   Next step
x + (x+64) = 1382      simplify
2x + 64 =1382           subtract 64 from each side of the = sign
2x = 1318                  divide both sides by 2
x = 659 pages in the first part
x + 64 = pages in the second part
659 + 64 = 723 pages in the second part

Answer 2

By translating the word problem into an algebraic equation, the number of pages of each part is calculated as:

• The first part = 659 pages
• The second part contains = 723 pages

To solve this, we can translate the word problem into an algebraic equation.

Thus:

• Let x represent the number of pages the first part has
• The second part will have (x + 64) pages

Since we are given that the total number pages of the Algebra text is 1382, therefore the following algebraic equation would be created:

(x + 64) + x = 1382

• Solve for x

x + 64 + x = 1382

• Combine like terms

2x + 64 = 1382

• Subtract 64 from both sides

2x = 1382 - 64

2x = 1318

• Divide both sides by 2

x = 659

Thus:

The first part contains x = 659 pages

The second part contains, x + 64 = 659 + 64 = 723 pages

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