Question

How many solutions are in the equation 3x^2+4x-7=0?

Answer 1

hello : 
 the equation 3x^2+4x-7=0 has 2 solutions because : ac < 0
 a = 3         b=4            c= -7
Δ = b²-4ac....... b² ≥ 0    and   -4ac > 0   ..... (ac < 0 )
coclusion : Δ>0.....(2 solutions)