Question

Which congruence theorem can be used to prove △MLQ ≅ △NPQ?

AAS
SSS
ASA
SAS

Answer 1

Answer: SSS

Proof:
In ΔMLQ and ΔNPQ,
MQ = NQ (given) S
Since Q is the midpoint of LP, by definition, LQ = QP (S)
LM = PN (given) S

∴ ΔMLQ ≡ ΔNPQ (SSS)

Answer 2

Answer:

SSS

Step-by-step explanation:

edge 2020

(the other person explained it good, so look above!)