Question

The sum of two numbers is 12.if three times the larger is added to twice the smaller the result is 33. Find the answer

Answer 1

so for this you start by figuring out all the numbers that add up to equal 12.
(0,12)(1,11)(2,10)(3,9)(4,8)(5,7)(6,6)
Then you put them into the equation 3l+2s=33 l=the larger number and s=the smaller number
To save space I'm only going to do the numbers that are the answers.
(3,9) 3(9)+2(3)=33
27+6=33
33=33
TADA