Question

A spinner numbered 1 to 6 is spun twice. What is the probability of getting a 4 on the first spin and an even number on the second spin?
A: 1/12
B: 1/4
C: 2/3
D: 1/6

Answer 1

The probability of getting a 4 is 1/6 and the probability of getting an even number is 3/6. So u multiply your two fractions so the answer is 3/36 which simplifies to 1/12. The answer is A.

Answer 2

The probability of getting a 4 on the first spin and an even number on the second spin is 1/12

What is probability?

"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."

Formula of the probability of an event A is:

P(A) = n(A)/n(S)

where,  n(A) is the number of favorable outcomes, n(S) is the total number of events in the sample space.

For given example,

a spinner numbered 1 to 6.

⇒ n(S) = 6

Let event A: getting a 4

⇒ n(A) = 1

so, the probability of getting 4 would be,

⇒ P(A) = n(A)/n(S)

⇒ P(A) = 1/6

Let event B: getting an even number

⇒ n(B) = 3

So, the probability of getting an even number would be,

⇒ P(B) = n(B)/n(S)

⇒ P(B) = 3/6

So, the required probability would be,

⇒ P = P(A) × P(B)

⇒ P = 1/6 × 3/6

⇒ P = 3/36

⇒ P = 1/12

Therefore, the probability of getting a 4 on the first spin and an even number on the second spin is 1/12

Learn more about probability here:

brainly.com/question/11234923

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