Question

The area on the wall covered by a rectangle poster is 320 square inches.The length of the poster is 1.25 times longer than the width of the poster. What are the dimensions of the poster?

Answer 1

If width is X, then length is 1.25X
1.25X·X=320
1.25X²=320
X²=256
X=16 or X=-16(not this one...)
width=16in
length=16x1.25=20in
Those are your answers.

Answer 2

Answer:

Length = 20 inches

Width = 16 inches

Step-by-step explanation:

The area on the wall covered by a rectangle poster is 320 square inches.

The length of the poster is 1.25 times longer than the width of the poster.

Let x be the width of the poster.

Length of the poster = 1.25x

Area of a rectangular poster is

$Area=length\times width$

$Area=1.25x\times x$

$320=1.25x^2$

Divide both sides by 1.25.

$\dfrac{320}{1.25}=x^2$

$256=x^2$

Taking square root on both sides.

$\pm 16=x$

The dimensions can not be negative. So, x=16.

Length of the poster = 1.25(16)=20

Therefore, the length of the poster is 20 inches and width of the poster is 16 inches.