Respuesta :
Answer:
The distance traveled by train in mountains is:
30 miles.
Time taken by train in mountains is:
0.8 hours( 48 minutes)
Step-by-step explanation:
Let the distance traveled by a train in plains be: x miles.
Time taken in plains to travel x mile= y hours.
Hence, distance traveled by train in mountains is: 300-x miles.
( Since a train travels a total of 300 miles)
Time taken in mountains is: 3.8-y hours
( Since train total takes a time of 3 hours and 48 minutes
3 hours and 48 minutes=3+48/60 hours
=3+0.8 hours
= 3.8 hours )
Now, average speed in plains is: 90 miles per hour.
i.e.
[tex]\dfrac{x}{y}=90------(1)[/tex]
Also,
Average speed of train in mountains is:37.5 miles per hour
i.e.
[tex]\dfrac{300-x}{3.8-y}=37.5------(2)[/tex]
From equation (1) we have:
[tex]x=90y[/tex]
on putting the value of x in equation (2) we get:
[tex]\dfrac{300-90y}{3.8-y}=37.5[/tex]
Now on solving we get:
y=3
Similarly x=270.
Hence, the distance traveled by the train in mountains is:
30 miles.
Time taken by train in mountains is: 48 minutes
( Since, 300-x=300-270=30 miles.
and 3.8-y=3.8-3=0.8 hours
which is equal to 48 minutes)
The train travelled 3 hours across the plain and 0.8 hours across the mountains.
Speed
Speed is the ratio of the distance travelled to time taken. It is given by:
Speed = distance / time
Let d₁ represent the distance covered in the plain at time t₁ and d₂ represent the distance covered in the mountain at time t₂.
- 90 = d₁ / t₁
- d₁ = 90t₁ (1)
Also:
- 37.5 = d₂ / t₂
- d₂ = 37.5t₂ (2)
d₁ + d₂ = 300
90t₁ + 37.5t₂ = 300 (3)
t₁ + t₂ = 3 hours 48 minutes
t₁ + t₂ = 3.8 (4)
Solving equations 3 and 4 simultaneously gives:
t₁ = 3, t₂ = 0.8
The train travelled 3 hours across the plain and 0.8 hours across the mountains.
Find out more on speed at: https://brainly.com/question/4931057