Answer=(x-2) (x+10)
For this it helps if you do a factoring table but since I will not for the sake of not having an image to show you, I will try and explain my answer.
The expression is:
x²+8x-20
In this case, since the x² doesn't have a number before it, we know that the beginning x's are solo, so we have...
(x+?)(x+?)
Now to solve the rest of the expression, we need to find two numbers that when multiplied equal -20 and when added equal 8.
a*b=-20
a+b=8
Lets look at the factor pairs of -20
(-1,20) or (1,-20) or (-2,10) or (2,-10) or (-4,5) or (4,-5)
Of all of these, only one pair have a sum of 8
So we can solve the expression
x²+8x-20=(x-2)(x+10)
