Respuesta :
so check the picture below
recall your SOH CAH TOA [tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \\ \quad \\\\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}[/tex]
which identity uses only
angle
opposite
adjacent?
well, is Ms Tangent.. thus [tex]\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(54^o)=\cfrac{1200}{x}[/tex]
solve for "x", make sure your calculator is in Degree mode, since the angle is in degrees
recall your SOH CAH TOA [tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \\ \quad \\\\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}[/tex]
which identity uses only
angle
opposite
adjacent?
well, is Ms Tangent.. thus [tex]\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(54^o)=\cfrac{1200}{x}[/tex]
solve for "x", make sure your calculator is in Degree mode, since the angle is in degrees

Answer:
The answer is 870 feet.
Step-by-step explanation:
Let's make a diagram (look at the end of the explanation).
We can solve this problem by using trigonometry.
Recall the trigonometric ratios:
[tex]sin(\alpha)=\frac{opposite}{hypotenuse}[/tex]
[tex]cos(\alpha)=\frac{adjacent}{hypotenuse}[/tex]
[tex]tan(\alpha)=\frac{opposite}{adjacent}[/tex]
As we know the size of the opposite cathetus to [tex]54^\circ[/tex] and we must work out the size of the adjacent cathetus (let's call it x), we can pick the tangent ratio (remember to use the degree -deg- mode of the calculator):
[tex]tan(54^\circ)=\frac{1200}{x}[/tex]
[tex]1.38=\frac{1200}{x}[/tex] (to 3 significant figures)
[tex] 1.38 x = 1200 [/tex]
[tex] x = 1200 : 1.38 [/tex]
[tex] x = 870 [/tex]
Therefore, you will have to walk 870 feet (to 3 sf) to meet your friend.
