Answer:
x = 7
Step-by-step explanation:
Using the logarithmic rules:
if [tex]\log_b x = a[/tex]
then
[tex]x = b^a[/tex]
Given the equation:
[tex]\log_6 (13-x) = 1[/tex]
Using logarithmic rules we have;
[tex]13-x = 6^1[/tex]
Simplify:
[tex]13-x = 6[/tex]
Subtract 13 from both sides we have;
-x = -7
Divide both sides by -1 we have;
x = 7
Therefore, the solution for the given equation is, 7
Answer:
Solve the equation log6(13 – x) = 1.
x = 7
Step-by-step explanation:
Got it from edge