Question

A rocket sled is tested at "5 g" (5 times the acceleration due to gravity). If the sled starts from rest at position do= 0.00, how long does it take to travel 441 meters? t = _____ s

Answer 1

d=at²
441m=(5*9.81m/s²)(t²)
t²=441/(5*9.81)
t≈√8.99
t≈3 sec

Answer 2

Answer:

It will take 4.24 seconds to travel 441 meters.

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case the velocity of body in vertical direction = 0 m/s, acceleration = 5g = 5 x 9.8 = 49 $m/s^2$, we need to calculate time when s = 441 meter.

Substituting

$441=0\times t+\frac{1}{2} \times 49\times t^2\\ \\ t = 4.24 seconds$

So it will take 4.24 seconds to travel 441 meters.