Respuesta :

Azieq
d = T2 - T1
d = 16 - 20
d = - 4

T15 = 20 + 14(-4)
= 20 - 56
= - 36

Answer:

The nth term for the arithmetic sequence is given by:

[tex]a_n=a_1+(n-1)d[/tex]

where,

[tex]a_1[/tex] is the first term.

d is the common difference of two consecutive term.

n is the number of terms.

As per the statement:

Given the sequence:

20, 16, 12, 8, 4

This is a arithmetic sequence.

Here, [tex]a_1=20[/tex] with common difference(d) = -4

Since,

16-20 = -4

12-16= -4

8-12 = -4

4-8 = -4

To find the 5th term of the sequence.

Substitute the given values and n = 15 we have;

[tex]a_{15} = 20+(15-1)(-4)[/tex]

⇒[tex]a_{15} = 20 + (14)(-4)[/tex]

⇒[tex]a_{15} = 20 - 56 = -36[/tex]

Therefore, the 5th term of the given sequence is, -36

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