Answer:
Given the equation:
[tex](x+7)(x-9) = 25[/tex]
Then;
[tex]x(x-9)+7(x-9) = 25[/tex]
Using the distributive property, [tex]a \cdot (b+c) = a\cdot b + a\cdot c[/tex]
[tex]x^2-9x+7x-63 =25[/tex]
Combine like terms;
[tex]x^2-2x-63 =25[/tex]
Subtract 25 from both sides we have;
[tex]x^2-2x-88=0[/tex]
Using completing square form:
Add and subtract [tex](\frac{2}{2})^2 =1[/tex] we have;
[tex]x^2-2x-88+1-1=0[/tex]
⇒[tex](x-1)^2-89 = 0[/tex]
Add 89 to both sides we have;
⇒[tex](x-1)^2=89[/tex]
Taking square root both sides we get;
[tex]x-1 = \pm \sqrt{89}[/tex]
Add 1 to both sides we have;
[tex]x = 1 \pm \sqrt{89}[/tex]
Therefore, the values of x are:
[tex]1+\sqrt{89}[/tex] and [tex]1 -\sqrt{89}[/tex]