Respuesta :
Answer:
Probability of pulling out a white sock = [tex]\frac{6}{10}[/tex].
Probability of pulling out another white sock = [tex]\frac{5}{9}[/tex].
Step-by-step explanation:
Given : A drawer of loose socks contains 2 red socks, 2 green socks, and 6 white socks.
To find : Which best describes how to determine the probability of pulling out a white sock, not replacing it, and pulling out another white sock.
Solution : We have given that red socks = 2.
green socks = 2
white socks = 6.
Total scoks = 10 .
Probability = [tex]\frac{number of favouable outcome }{total number of outcomes}[/tex].
Probability of pulling out a white sock = [tex]\frac{6}{10}[/tex].
Not replacing it ,
Now , we left only total 9 socks and 5 white socks
Probability of pulling out another white sock = [tex]\frac{5}{9}[/tex].
Therefore, Probability of pulling out another white sock = [tex]\frac{5}{9}[/tex].
The probability of pulling out a white sock, not replacing it, and pulling out another white sock is 1/3.
Number of red socks =2
Number of green socks =2
Number of white socks =6
Total socks =10
What is probability?
Probability is the quantification of the possibilities of an event.
Number of ways to select 1 white sock out of 6 white socks= [tex]^6C_1[/tex]
Number of ways to select 1 white sock out of 10 socks = [tex]^10C_1[/tex]
So, the probability of pulling out a white sock first time = [tex]\frac{^6C_1}{^10C_1}=\frac{6}{10} =\frac{3}{5}[/tex]
Number of white socks left =5
Total number of socks left =9
So, the probability of pulling out a white sock a second time(without replacement) = [tex]\frac{5}{9}[/tex]
Total probability = [tex]\frac{3}{5} *\frac{5}{9} =\frac{3}{9} =\frac{1}{3}[/tex]
Thus, the probability of pulling out a white sock, not replacing it, and pulling out another white sock is 1/3.
To get more about probability visit:
https://brainly.com/question/24756209
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