Answer:
10th term = (-137)
Step-by-step explanation:
This is an arithmetic sequence. Each term of this sequence is obtained by subtracting 3 from the previous term.
n = 50
Common difference = second term - first term
d = 7 - 10
d = -3
a =first term = 10
[tex]\boxed{\bf T_n = a +(n- 1)*d}[/tex]
[tex]\sf T_{50}=10 + (50 - 1) * (-3)[/tex]
= 10 + 49 * (-3)
= 10 - 147
= -137