Question

Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that Allen will NOT select a consonant?

Answer 1

im pritty sure it would be 30%

Answer 2

Answer: $\text{P(Not consonant)}=\frac{3}{8}$

In decimal, $0.375$

In percentage,$37.5\%$

Step-by-step explanation:

Given: Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly.

Total number of letters= 8

The number of consonant=5 (S, L, C, T, D )

The number of letters which are not consonants (vowels)=8-5=3

Now, the probability that Allen will NOT select a consonant is given by :-

$\text{P(Not consonant)}=\frac{\text{number of non consonant letters}}{\text{total letters}}$

$\\\Rightarrow\ \text{P(Not consonant)}=\frac{3}{8}$

In decimal, $\frac{3}{8}=0.375$

In percentage,$\frac{3}{8}\times100=37.5\%$