Respuesta :

1/root(5-x) = 1/(root5 * root 1- x/5)
1/root5 * (1-x/5)^-1/2

Using the 1st 2 terms of the binomial expansion 1 +nx:
1/root5 ( 1 + x/10)
= X/10root5 + 1/root5

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