A gardener is planting herbs in a line in a garden. Basil is located at point B, thyme is located at point T, and oregano is located at point O.

a line segment B O with point T on the line segment between B and O

If the distance between the basil and the oregano is 16 in and the distance between the thyme and the oregano is 4 in, what is the distance between the basil and the thyme?

24 in
20 in
12 in
10 in

Respuesta :

Answer:

Based on the given information, we have a line segment BO with point T located on the line segment between B and O. The distance between B and O is given as 16 inches, and the distance between T and O is given as 4 inches.

To find the distance between the basil (B) and the thyme (T), we can subtract the distance between T and O from the distance between B and O:

Distance between B and T = Distance between B and O - Distance between T and O

Distance between B and T = 16 inches - 4 inches = 12 inches.

Therefore, the distance between the basil and the thyme is 12 inches.

Dang that's too much points

Answer:

Step-by-step explanation:

Let point B be the location of basil.

Let point T be the location of thyme.

Let point O be the location of oregano.

We are told that BO is a line segment with point T on the line segment between B and O. Therefore:

[tex]\sf \overline{BT} + \overline{TO} = \overline{BO}[/tex]

We are told that the distance between B and O is 16 in, and the distance between T and O is 4 in. Therefore:

  • [tex]\sf \overline{BO} = 16[/tex]
  • [tex]\sf \overline{TO} = 4[/tex]

To find the distance between the basil (B) and the thyme (T), substitute the given values of BO and TO into the found equation, and solve for BT:

[tex]\begin{aligned}\sf \overline{BT} + \overline{TO} &=\sf \overline{BO}\\\sf \overline{BT} + 4 &= \sf 16\\\sf \overline{BT} + 4 - 4 &= \sf 16 - 4\\\sf \overline{BT} &= \sf 12\end{aligned}[/tex]

Therefore, the distance between the basil (B) and the thyme (T) is 12 inches.

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