Question

A lever has an effort arm that is 8 meters long and the resistance arm that is 1.5 meters long, how much effort is needed to lift 209 newton weight?

Answer 1

Answer: The effort force will be 8190.2 N.

Explanation:

Given that,

Effort arm = 8 m

Resistance arm = 1.5 m

Weight = 209 N

We know that,

Effort force multiply by effort arm=Weight multiply by resistance arm

$F_{e}\times 8=209\times 1.5$

$F_{e}=8190.2 N$

Hence, The effort force will be 8190.2 N.

Answer 2

The effort or the force needed to lift a 209-newton weight will be 8190.2 N.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The given data in the problem is;

E is the effort arm = 8 m

R is the resistance arm = 1.5 m

W is the weight = 209 N

$\rm F_e$ is the effort force

Force is defined as the product of mass and acceleration. Its unit is Newton.

Effort force multiplied by the effort arm is equal to the weight multiplied by the resistance arm.

$\rm F_e \times E = W \times R \\\\ \rm F_e = \frac{W \times R}{E } \\\\ \rm F_e = \frac{W \times R}{E } \\\\ \rm F_e = \frac{209 \times 1.5}{8 } \\\\ \rm F_e = 8190.2\ N$

Hence, the effort force will be 8190.2 N.

To learn more about the force refer to the link;

https://brainly.com/question/26115859