Respuesta :
The chemical reaction would be as follows:
Ca(OH)2 + 2HNO3 = Ca(NO3)2 + 2H2O
We are given the concentrations and volumes of the substances. We use these values and the relationships to calculate the molarity of the Ca(OH2).
0.02 mol HNO3 / L (.02 L) ( 1 mol Ca(OH)2 / 2 mol HNO3 ) = 0.0002 mol Ca(OH)2
Molarity = 0.0002 / 0.010 = 0.02 M Ca(OH)2
Ca(OH)2 + 2HNO3 = Ca(NO3)2 + 2H2O
We are given the concentrations and volumes of the substances. We use these values and the relationships to calculate the molarity of the Ca(OH2).
0.02 mol HNO3 / L (.02 L) ( 1 mol Ca(OH)2 / 2 mol HNO3 ) = 0.0002 mol Ca(OH)2
Molarity = 0.0002 / 0.010 = 0.02 M Ca(OH)2
Answer: Molarity of Calcium Hydroxide solution is 0.04M.
Explanation: We are given 10.00 mL of Calcium hydroxide solution which is neutralized by 20.00 mL of 0.02M of [tex]HNO_3[/tex] solution.
To find out the molarity of calcium hydroxide, we use the formula:
[tex]M_1V_1=M_2V_2[/tex]
[tex]M_{Ca(OH)_2}\times V_{Ca(OH)_2}=M_{HNO_3}\times V_{HNO_3}[/tex]
Putting the values in above equation, we get
[tex]M_{Ca(OH)_2}\times 10=0.02\times 20[/tex]
[tex]M_{Ca(OH)_2}=0.04M[/tex]
