Answer:
[tex]y = \dfrac{1}{4}x+9[/tex]
Step-by-step explanation:
The product of slope of perpendicular lines are (-1).
Slope intercept form: y = mx +b
Here, m is slope and b is y-intercept.
y = -4x - 2.
Slope m₁ = -4
[tex]\text{slope of the required line = m =$\dfrac{-1}{m_1}$}[/tex]
[tex]\sf m = \dfrac{-1}{-4}=\dfrac{1}{4}[/tex]
The line is passing through the point(0 , 9)
Substitute the slope and point in the equation of line in point-slope form:
[tex]\boxed{y - y_1 = m(x - x_1) }[/tex]
[tex]y - 9 = \dfrac{1}{4}(x - 0)\\\\\\y - 9 = \dfrac{1}{4}x\\\\~~~~~~ y = \dfrac{1}{4}x+9[/tex]