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Please also explain your answer!

1) [tex] x^{2} [/tex] + 64 = 0

2) What is the side length of a square with an area of [tex] 144x^{2} [/tex]

Thanks in advance :)

Respuesta :

x² + 64 = 0
⇒ x² = -64
But x² can not be negative. So there is no answer
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area of square = 144x²
side = √144x² = 12x
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