Question

The graph plots four equations, A, B, C, and D:

Line A joins ordered pair negative 6, 16 and 9, negative 4. Line B joins ordered pair negative 2, 20 and 8, 0. Line C joins ordered pair negative 7, negative 6 and 6, 20. Line D joins ordered pair 7, 20 and 0, negative 7.

Which pair of equations has (2, 12) as its solution?

Equation A and Equation C
Equation B and Equation C
Equation C and Equation D
Equation B and Equation D

Answer 1

The best answer among the following choices that the question ask to find the pair of equations has (4,8) as its solution and the best answer among them is letter B. equation B and equation C. I hope you are satisfied with my answer and feel free to ask for more

Answer 2

Option B is correct. The pair of equations that has (2, 12) as its solution is lines B and C

The standard form of an equation is y = mx + b where:

m is the slope

b is the y-intercept

For line B with coordinate (-2, 20) and (8, 0)

Get the slope of the line:

$m=\frac{0-20}{8+2}\\m=\frac{-20}{10}\\m=-2$

Get the y-intercept

0 = -2(8) + b

b = 16

The required equation is y = -2x + 16

To check if (2, 12) is a solution, substitute x = 2 to check if we are going to have 12 as the y value.

y = -2(2)+16

y=-4+16

y = 12

This shows that the equation with coordinates (-2, 20) and (8, 0) has a solution of (2, 12).

For line C with coordinate (-7, -6) and (6, 20)

Get the slope of the line:

$m=\frac{20+6}{7+6} \\m=\frac{26}{13}\\m=2$

Get the y-intercept

20 = 2(6) + b

b = 20-12

b = 8

The required equation is y = 2x + 8

To check if (2, 12) is a solution, substitute x = 2 to check if we are going to have 12 as the y value.

y = 2(2)+8

y=-4+8

y = 12

This shows that the equation with coordinates (-7, -6) and (6, 20) has a solution of (2, 12).

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