At the football game they sold $4 pizzas and $2 sodas which made the school$260 the number of Sodas sold was five more than three times a number of pizzas sold determine the amount of pizza and sodad sold

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[tex]\Huge \textsf{Answer:\fbox{25 pizzas and 80 sodas sold.}}}[/tex]

[tex]\Huge \textsf{Step-by-step explanation}[/tex]

[tex]\LARGE \bold{\textsf{Step 1: Assign Variables}}[/tex]

[tex]\textsf{Let's assign a variable for the number of pizzas sold, we will call it \textit{"p."}}\\\textsf{And we will assign the variable\textit{"s"} for the number of sodas sold.}[/tex]

[tex]\LARGE \bold{\textsf{Step 2: Write equations based on the given information}}[/tex]

[tex]\large \bold{ \textsf{From the problem, we know that:}}[/tex]

[tex]\bullet \textsf{The school made \$260 from seeling 4 pizzas and 2 sodas.}\\\\\bullet \textsf{The number of sodas sold was five more than three times the number of pizzas sold.}[/tex]

[tex]\large \bold{ \textsf{We can use this information to write two equations:}}[/tex]

[tex]\text{Equation 1} : 4p + 2s = 260 \text{(since each pizza costs \$4 and each soda costs \$2)}[/tex]

[tex]\text{Equation 2} : s = 3p + 5 \text{(The number of sodas sold was 3 times the number of}\\\text{pizzas sold plus 5)}[/tex]

[tex]\LARGE \bold{\textsf{Step 3: Solve the system of equations}}[/tex]

[tex]\large \textsf{To solve the system of equations, we can substitute Equation 2 into Equation}\\\textsf{1 for \textit{"p"}:}[/tex]

[tex]\bullet \textsf{4\textit{p} + 2\textit{s} = 260}\\\\\bullet \textsf{4\textit{p} + 2(3\textit{p} + 5) = 260}[/tex]

[tex]\large \textsf{Simplifying this expression gives us:}[/tex]

[tex]\textsf{10\textit{p} + 10 = 260}[/tex]

[tex]\large \textsf{Subtracting 10 from both sides:}[/tex]

[tex]\textsf{10\textit{p} = 250}[/tex]

[tex]\large \textsf{Dividing both sides by 10}[/tex]

[tex]\textsf{\textit{p} = 25}[/tex]

[tex]\large \textsf{Now that we know the number of pizzas sold, we can use Equation 2 to find}\\\textsf{the number of sodas sold:}[/tex]

[tex]\bullet \textsf{\textit{s} = 3\textit{p} + 5}\\\\\bullet \textsf{\textit{s} = 3(25) + 5}\\\\\bullet \textsf{\textit{s} = 75 + 5}\\\\\bullet \textsf{\textit{s} = 80}[/tex]

[tex]\large \textsf{So, 25 pizzas and 80 sodas were sold.}[/tex]

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