Use any test to determine whether the series is absolutely convergent, conditionally convergent, or divergent. [infinity]Σₙ₌₁ (-1)ⁿarctan(n) / n¹³ We know that the arctangent function has lower and upper limits
-π/2 < arctan(x) < ___
Therefore |(-1)ⁿarctan(n) / n¹³ < ___ /n¹³.
