Answer:
c. it would decrease by a factor of 2.
Explanation:
As we know that centripetal force on Earth due to Sun is due to gravitational attraction force of Sun
Now we will have
[tex]F_c = \frac{GMm}{r^2}[/tex]
[tex]\frac{mv^2}{r} = \frac{GMm}{r^2}[/tex]
now we have
[tex]v = \sqrt{\frac{GM}{r}}[/tex]
now if the orbital radius or the distance from sun is increased by factor of 4
so the orbital speed is changed by
[tex]v' = \sqrt{\frac{GM}{4r}}[/tex]
so the speed would be given as
[tex]v' = \frac{v}{2}[/tex]
so it is half of the initial speed