Question

an object accelerates from rest, with a constant acceleration of 6.4 m/s^2, what will its velocity be after 7s?

Answer 1

a = v/t
hence v = at
= 6.4 * 7

Answer 2

Using the first kinematic equation,

v(final) = v(inital) + at
v(final) = 0 + (6.4 m/s^2)(7 s)
v(final) = 44.8 m/s