Question

In a class of 42 students, the number of boys is 2/5 of the girls. Find the number of boys and girls in the class.

Answer 1

Answer:

BOYS = 30.

GIRLS = 12.

Step-by-step explanation:

Boys: B

Girls: G

B = (2/5)G

B + G = 42.

(2/5)G + G = 42

2G + 5G = 210

7G = 210

G = 210/7

G = 30.

B = (2/5)G

B = (2/5)(30)

B = 60/5

B = 12.

Answer 2

Answer:

$\Huge \boxed{\bold{\text{12 Boys}}}$

$\Huge \boxed{\bold{\text{30 Girls}}}$

Step-by-step explanation:

Let the number of girls be $g$ and the number of boys be $b$.

According to the problem: $b = \frac{2}{5} \times g$

We also know that the total number of students is 42, so $b + g = 42$.

Now, we have two equations with two variables:

1.  $b = \frac{2}{5} \times g$
2.  $b + g = 42$

We can solve these equations to find the values of $b$ and $g$.

Step 1: Solve for $\bold{b}$ in terms of $\bold{g}$

From the first equation, we have$b = \frac{2}{5} \times g$

Step 2: Substitute the expression for $\bold{b}$ into the second equation

Replace $b$ in the second equation with the expression we found in step 1.

$\frac{2}{5} \times g + g = 42$

Step 3: Solve for $\bold{g}$

Now, we have an equation with only one variable, $g$:

$\frac{2}{5} \times g + g = 42$

To solve for $g$, first find a common denominator for the fractions:

$\frac{2}{5} \times g + \frac{5}{5} \times g = 42$

Combine the fractions:

$\frac{7}{5} \times g = 42$

Now, multiply both sides of the equation by $\frac{5}{7}$ to isolate $g$:

• $g = 42 \times \frac{5}{7}$
• $g = 30$

Step 4: Find the value of $\bold{b}$

Now that we have the value of $g$, we can find the value of $b$ using the first equation:

• $b = \frac{2}{5} \times g$
• $b = \frac{2}{5} \times 30$
• $b = 12$

So, there are 12 boys and 30 girls in the class.

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