[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{-\frac{3}{5}})\hspace{10em} \stackrel{slope}{m} ~=~ - 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-\frac{3}{5})}=\stackrel{m}{- 1}(x-\stackrel{x_1}{0}) \implies y +\cfrac{3}{5} = - 1 ( x -0) \\\\\\ y+\cfrac{3}{5}=-x\implies y=-x-\cfrac{3}{5}[/tex]
Answer:
y = -x-3/5
Step-by-step explanation:
We are given that a line goes through the point (0, -3/5) and has a slope (m) of -1.
We want to find the equation of this line.
Notice how the answers are written in slope-intercept form, which is y=mx+b, where m is the slope and b is the value of y at the y-intercept.
As we are given the slope, we can immediately plug that into the equation.
Substitute m as -1.
y = -1x + b
We can rewrite it to become:
y = -x + b
Now, notice that (0, -3/5), the point we are given is the y-intercept of the line (as the value of x is 0).
So, substitute -3/5 as b in the equation.
y = -x-3/5
The answer is the first one :).
